If P Is a Prime Number Which Divides A2, Then P Divides A, Where A Is a Positive Integer
We know that a number which cannot be written in the form of
, where p and q are integers and q ≠ 0, is known as an irrational number.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_65af025c.gif)
For example: all numbers of the form
, where p is a prime number such as
etc., are irrational numbers.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m430aac4e.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m7a2a72bb.gif)
How can we prove that these are irrational numbers?
We can prove this by making use of a theorem which can be stated as follows.
“If p divides a2, then p divides a (where p is a prime number and a is a positive integer)”. |
So go through the given video to understand the application of the above stated property.
Similarly, we can prove that square roots of other prime numbers like
, etc. are irrational numbers.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m2ba2a852.gif)
Besides these irrational numbers, there are some other irrational numbers like
etc.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_37a6f831.gif)
We can also prove why these numbers are irrational. Before this, let us first see what happens to irrational numbers, when we apply certain mathematical operations on them.
- Addition or subtraction of two irrational numbers gives a rational or an irrational number.
- Addition or subtraction of a rational and an irrational number gives an irrational number.
- Multiplication of a non-zero rational number and an irrational number gives an irrational number.
- Multiplication of two irrational numbers gives a rational or an irrational number.
We will now prove that
is irrational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_370ecc6f.gif)
We know that
is irrational (as proved before).
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m74e5c629.gif)
Now, the multiplication of a rational and an irrational number gives an irrational number.
Therefore,
is an irrational number.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m69aacebe.gif)
Let us now try to understand the concept further through some more examples.
Example 1:
Prove that
is irrational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m40fe6a3.gif)
Solution:
Let us assume that
is not irrational, i.e.
is a rational number.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m40fe6a3.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m40fe6a3.gif)
Then we can write
, where a and b are integers andb ≠ 0.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_7a3fdcf1.gif)
Let a and b have a common factor other than 1.
After dividing by the common factor, we obtain
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_3244d9bd.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_72da52ee.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m6f130f1d.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_1bf3bd84.gif)
As c, d and 2 are integers,
and
are rational numbers.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m2f1cbb58.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_21c6157c.gif)
Thus,
is rational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_4f6efde0.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m4bc7e987.gif)
This is a contradiction as
is irrational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_45fefb98.gif)
Therefore, our assumption that
is rational is wrong.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m40fe6a3.gif)
Hence,
is irrational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m40fe6a3.gif)
Example 2:
Prove that
is irrational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m1c9f4a1d.gif)
Solution:
Let us assume
is rational. Then, we can write
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m1c9f4a1d.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m1495e0d7.gif)
where a and b are co-prime and b ≠ 0.
⇒![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_26104d17.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_26104d17.gif)
Now, as a and b are integers,
is rational or
is a rational number.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m23338b16.gif)
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_25487305.gif)
This means that
is rational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_6af01362.gif)
This is a contradiction as
is irrational.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_6af01362.gif)
Therefore, our assumption that
is rational is wrong.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m1c9f4a1d.gif)
Hence,
is an irrational number.
![](http://cbse.meritnation.com/img/lp/1/10/9/128/157/414/454/10.1.1.3.1_ok_html_m1c9f4a1d.gif)
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